Job's Method for Determination of Stoichiometry

Job's Method, also called the Method of Continuous Variation, is a simple and effective approach to the determination of chemical reaction stoichiometry. We will discuss it in the context of generic reaction (1),

(1): aA + bB <===> dD

which can be rewritten in the form of (2) by dividing all coefficients by "a".

(2): A + kB <===> mD

where k = b/a and m = d/a. Job's method is based on the following fact: if a series of solutions is prepared, each containing the same total number of moles of A and B, but a different ratio, R, of moles B to moles A, the maximum amount of product, D, is obtained in the solution in which R = k (the stoichiometric ratio). To implement Job's Method experimentally, one prepares a series of solutions containing a fixed total number of moles of A and B, but in which the R is systematically varied from large to small, and measures the amount of product obtained in each solution. One then plots amount of product versus R, and obtains a maximum at the initially-unknown value of k.

That the maximum amount of product should occur at the stoichiometric ratio can be justified both intuitively and mathematically. The intuitive justification runs as follows. When R is greater than k, there is an excess of reagent B, so reagent A is the limiting reagent. As R is systematically decreased toward k (i.e., as moles A increases and moles B decreases such that moles A + moles B stays constant) the amount of product increases with the amount of limiting reagent, A, until R becomes equal to k. In contrast, when R is less than k, there is an excess of reagent A, and B is limiting. As R is systematically increased toward k (i.e., as moles B increases and moles A decreases), the amount of product increases with the amount of limiting reagent B, until R becomes = k. Putting this all together, we see that as R is varied over the range from zero to the maximum value investigated, the amount of product obtained increases until R = k, then decreases as R becomes larger than k. This demonstrates Job's Method intuitively.

The mathematical justification is also quite simple. We use variable "x" to represent the moles of A in a particular solution, and assume that the total moles of A and B is to be kept at 1.0 throughout the series of solutions. Then in each solution it will be true that

x = moles A
1-x = moles B

Our goal is to show that the maximum amount of product is obtained when R = moles B/moles A = (1-x)/x is equal to k. We approach this by finding the value of x that maximizes product.

According to equation (2), if x is less than the stoichiometrically correct amount of A, then A is limiting and moles product = mx. A plot of moles product versus x over a series of solutions should be linear, with slope m. Similarly, if x exceeds the stoichiometrically correct amount of A, then B is limiting and moles product = m(1-x)/k. A plot of moles product versus x over a series of solutions should also be linear, with slope = -m/k. The first plot will proceed up to the right as x increases. The second plot will proceed down to the right as x increases. At some point then, the two straight lines will intersect. At the intersection, they have a point in common. The value of x corresponding to this point is obtained by equating the ordinate values and solving for x:

mx = m(1-x)/k

Solving gives x = 1/(1+k).
Substituting in the expression for R, (1-x)/x, we find that the two lines intersect when

R = (1-x)/x = {1 - [1/(1+k)]}/[1/(1+k)] = k.

Because the amount of product increases as k is approached from either direction, the point of intersection of the lines occurs at the maximum amount of product obtainable. We have therefore shown that maximum product is obtained when R = k. This is what we set out to demonstrate.

Example: A and B are known to react to form D, but the stoichiometry is uncertain. A Job's Method study yields the following data. Plot quantity of product versus moles A to determine the stoichiometry.

moles Amoles Bgrams product
0.21.82.5
0.31.73.75
0.41.65.0
0.61.44.38
0.81.23.75
1.01.03.12

The plot is shown in Figure 1. The value of k is clearly 4, because at the maximum, moles B/moles A = 1.6/0.4 = 4.